Solve {l}{3{(x-2)}+8=2}{y={(x+3)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 3 {(x - 2)} + 8 = 2 }\\ { y = {(x + 3)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=3$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 3 by x-2.

$$3x-6+8=2$$

Add -6 and 8 to get 2.

$$3x+2=2$$

Subtract 2 from both sides.

$$3x=2-2$$

Subtract 2 from 2 to get 0.

$$3x=0$$

Divide both sides by 3. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=0+3$$

Add 0 and 3 to get 3.

$$y=3$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=3$$

The system is now solved.

$$x=0 y=3 z=3$$