Solve {l}{24x+16=80}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 24 x + 16 = 80 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$$

Solution Steps

Consider the first equation. Subtract 16 from both sides.

$$24x=80-16$$

Subtract 16 from 80 to get 64.

$$24x=64$$

Divide both sides by 24.

$$x=\frac{64}{24}$$

Reduce the fraction \frac{64}{24} to lowest terms by extracting and canceling out 8.

$$x=\frac{8}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{8}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{8}{3}$$

The system is now solved.

$$x=\frac{8}{3} y=\frac{8}{3} z=\frac{8}{3}$$