Solve {l}{2200+150*n=2200*1}{o=0*5^n}{text{Solvefor}ptext{where}}{p=o}

$$\left. \begin{array} { l } { 2200 + 150 \cdot n = 2200 \cdot 1 }\\ { o = 0 \cdot 5 ^ {n} }\\ { \text{Solve for } p \text{ where} } \\ { p = o } \end{array} \right.$$

Solve for n, o, p

$$p=0$$

Solution Steps

Consider the first equation. Multiply 2200 and 1 to get 2200.

$$2200+150n=2200$$

Subtract 2200 from both sides.

$$150n=2200-2200$$

Subtract 2200 from 2200 to get 0.

$$150n=0$$

Divide both sides by 150. Zero divided by any non-zero number gives zero.

$$n=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$o=0\times 5^{0}$$

Calculate 5 to the power of 0 and get 1.

$$o=0\times 1$$

Multiply 0 and 1 to get 0.

$$o=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$p=0$$

The system is now solved.

$$n=0 o=0 p=0$$