Solve {l}{2x=19}{y=x^2}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 2 x = 19 }\\ { y = x ^ {2} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{361}{4} = 90\frac{1}{4} = 90.25$$

Solution Steps

Consider the first equation. Divide both sides by 2.

$$x=\frac{19}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(\frac{19}{2}\right)^{2}$$

Calculate \frac{19}{2} to the power of 2 and get \frac{361}{4}.

$$y=\frac{361}{4}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{361}{4}$$

The system is now solved.

$$x=\frac{19}{2} y=\frac{361}{4} z=\frac{361}{4}$$