Solve {l}{2x+1/4=2}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 2 x + \frac{1}{4} = 2 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=\frac{7}{8}=0.875$$

Solution Steps

Consider the first equation. Subtract \frac{1}{4} from both sides.

$$2x=2-\frac{1}{4}$$

Subtract \frac{1}{4} from 2 to get \frac{7}{4}.

$$2x=\frac{7}{4}$$

Divide both sides by 2.

$$x=\frac{\frac{7}{4}}{2}$$

Express \frac{\frac{7}{4}}{2} as a single fraction.

$$x=\frac{7}{4\times 2}$$

Multiply 4 and 2 to get 8.

$$x=\frac{7}{8}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{7}{8}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{7}{8}$$

The system is now solved.

$$x=\frac{7}{8} y=\frac{7}{8} z=\frac{7}{8}$$