Solve {l}{2*x+0*0*3=0*0*0*4}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 2 \cdot x + 0 \cdot 0 \cdot 3 = 0 \cdot 0 \cdot 0 \cdot 4 }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Multiply 0 and 0 to get 0.

$$2x+0\times 3=0\times 0\times 0\times 4$$

Multiply 0 and 3 to get 0.

$$2x+0=0\times 0\times 0\times 4$$

Anything plus zero gives itself.

$$2x=0\times 0\times 0\times 4$$

Multiply 0 and 0 to get 0.

$$2x=0\times 0\times 4$$

Multiply 0 and 0 to get 0.

$$2x=0\times 4$$

Multiply 0 and 4 to get 0.

$$2x=0$$

Divide both sides by 2. Zero divided by any non-zero number gives zero.

$$x=0$$

The system is now solved.

$$x=0 y=0 z=0$$