Solve {l}{18y=362}{z=-2y-60}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 18 y = 362 }\\ { z = -2 y - 60 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, z, a

$$a = -\frac{902}{9} = -100\frac{2}{9} \approx -100.222222222$$

Solution Steps

Consider the first equation. Divide both sides by 18.

$$y=\frac{362}{18}$$

Reduce the fraction \frac{362}{18} to lowest terms by extracting and canceling out 2.

$$y=\frac{181}{9}$$

Consider the second equation. Insert the known values of variables into the equation.

$$z=-2\times \frac{181}{9}-60$$

Multiply -2 and \frac{181}{9} to get -\frac{362}{9}.

$$z=-\frac{362}{9}-60$$

Subtract 60 from -\frac{362}{9} to get -\frac{902}{9}.

$$z=-\frac{902}{9}$$

Consider the third equation. Insert the known values of variables into the equation.

$$a=-\frac{902}{9}$$

The system is now solved.

$$y=\frac{181}{9} z=-\frac{902}{9} a=-\frac{902}{9}$$