Solve {l}{100=10x}{y=--20x}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 100 = 10 x }\\ { y = --20 x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=200$$

Solution Steps

Consider the first equation. Divide both sides by 10.

$$\frac{100}{10}=x$$

Divide 100 by 10 to get 10.

$$10=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=10$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(-\left(-20\right)\right)\times 10$$

The opposite of -20 is 20.

$$y=20\times 10$$

Multiply 20 and 10 to get 200.

$$y=200$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=200$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=200$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=200$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=200$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=200$$

The system is now solved.

$$x=10 y=200 z=200 a=200 b=200 c=200 d=200$$