Solve {l}{10-0*0*0*2x=1x+2}{y=3500}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 10 - 0 \cdot 0 \cdot 0 \cdot 2 x = 1 x + 2 }\\ { y = 3500 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=3500$$

Solution Steps

Consider the first equation. Multiply 0 and 0 to get 0.

$$10-0\times 0\times 2x=1x+2$$

Multiply 0 and 0 to get 0.

$$10-0\times 2x=1x+2$$

Multiply 0 and 2 to get 0.

$$10-0x=1x+2$$

Anything times zero gives zero.

$$10-0=1x+2$$

Subtract 0 from 10 to get 10.

$$10=1x+2$$

Swap sides so that all variable terms are on the left hand side.

$$1x+2=10$$

Subtract 2 from both sides.

$$1x=10-2$$

Subtract 2 from 10 to get 8.

$$1x=8$$

Divide both sides by 1.

$$x=8$$

The system is now solved.

$$x=8 y=3500 z=3500$$