Solve {l}{1-60*4+y+{(-9*0*55)}=-70}{z=14}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 1 - 60 \cdot 4 + y + {(-9 \cdot 0 \cdot 55)} = -70 }\\ { z = 14 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, z, a

$$a=14$$

Solution Steps

Consider the first equation. Multiply 60 and 4 to get 240.

$$1-240+y-9\times 0\times 55=-70$$

Subtract 240 from 1 to get -239.

$$-239+y-9\times 0\times 55=-70$$

Multiply -9 and 0 to get 0.

$$-239+y+0\times 55=-70$$

Multiply 0 and 55 to get 0.

$$-239+y+0=-70$$

Add -239 and 0 to get -239.

$$-239+y=-70$$

Add 239 to both sides.

$$y=-70+239$$

Add -70 and 239 to get 169.

$$y=169$$

The system is now solved.

$$y=169 z=14 a=14$$