Solve {l}{{(2^4-3^2)}x-7*9-2x=5^2-2}{y=9}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { {(2 ^ {4} - 3 ^ {2})} x - 7 \cdot 9 - 2 x = 5 ^ {2} - 2 }\\ { y = 9 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=9$$

Solution Steps

Consider the first equation. Calculate 2 to the power of 4 and get 16.

$$\left(16-3^{2}\right)x-7\times 9-2x=5^{2}-2$$

Calculate 3 to the power of 2 and get 9.

$$\left(16-9\right)x-7\times 9-2x=5^{2}-2$$

Subtract 9 from 16 to get 7.

$$7x-7\times 9-2x=5^{2}-2$$

Multiply 7 and 9 to get 63.

$$7x-63-2x=5^{2}-2$$

Combine 7x and -2x to get 5x.

$$5x-63=5^{2}-2$$

Calculate 5 to the power of 2 and get 25.

$$5x-63=25-2$$

Subtract 2 from 25 to get 23.

$$5x-63=23$$

Add 63 to both sides.

$$5x=23+63$$

Add 23 and 63 to get 86.

$$5x=86$$

Divide both sides by 5.

$$x=\frac{86}{5}$$

The system is now solved.

$$x=\frac{86}{5} y=9 z=9$$