Solve {l}{{(1+2)}z=2i}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { {(1 + 2)} z = 2 i }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for z, a, b

$$b=\frac{2}{3}i\approx 0.666666667i$$

Solution Steps

Consider the first equation. Add 1 and 2 to get 3.

$$3z=2i$$

Divide both sides by 3.

$$z=\frac{2i}{3}$$

Divide 2i by 3 to get \frac{2}{3}i.

$$z=\frac{2}{3}i$$

Consider the second equation. Insert the known values of variables into the equation.

$$a=\frac{2}{3}i$$

Consider the third equation. Insert the known values of variables into the equation.

$$b=\frac{2}{3}i$$

The system is now solved.

$$z=\frac{2}{3}i a=\frac{2}{3}i b=\frac{2}{3}i$$