Solve for x, y, z
z=-28
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y=x \frac{x+4}{3}+\frac{5x-10}{x-2}=\frac{9x-3}{1-3x} z=y
Reorder the equations.
z=x
Substitute x for y in the equation z=y.
x=-28
Solve \frac{x+4}{3}+\frac{5x-10}{x-2}=\frac{9x-3}{1-3x} for x.
z=-28
Substitute -28 for x in the equation z=x.
y=-28
Substitute -28 for x in the equation y=x.
x=-28 y=-28 z=-28
The system is now solved.
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