Solve {l}{1/25.4=0.33/x}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { \frac{1}{25.4} = \frac{0.33}{x} }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=8.382$$

Solution Steps

Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$x\times \frac{1}{25.4}=0.33$$

Expand \frac{1}{25.4} by multiplying both numerator and the denominator by 10.

$$x\times \frac{10}{254}=0.33$$

Reduce the fraction \frac{10}{254} to lowest terms by extracting and canceling out 2.

$$x\times \frac{5}{127}=0.33$$

Multiply both sides by \frac{127}{5}, the reciprocal of \frac{5}{127}.

$$x=0.33\times \frac{127}{5}$$

Multiply 0.33 and \frac{127}{5} to get \frac{4191}{500}.

$$x=\frac{4191}{500}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{4191}{500}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{4191}{500}$$

The system is now solved.

$$x=\frac{4191}{500} y=\frac{4191}{500} z=\frac{4191}{500}$$