Solve {c}{y=2x^2-4x-3}{x=4}

$$\left. \begin{array} { c } { y = 2 x ^ { 2 } - 4 x - 3 } \\ { x = 4 } \end{array} \right.$$

Solve for y, x

$$x=4$$

$$y=13$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=2\times 4^{2}-4\times 4-3$$

Calculate 4 to the power of 2 and get 16.

$$y=2\times 16-4\times 4-3$$

Multiply 2 and 16 to get 32.

$$y=32-4\times 4-3$$

Multiply -4 and 4 to get -16.

$$y=32-16-3$$

Subtract 16 from 32 to get 16.

$$y=16-3$$

Subtract 3 from 16 to get 13.

$$y=13$$

The system is now solved.

$$y=13 x=4$$