Solve {c}{xa^2+6a+9*3a-9}{a^2-9quada+3}

$$\left. \begin{array} { c } { x a ^ { 2 } + 6 a + 9 \cdot 3 a - 9 } \\ { a ^ { 2 } - 9 \quad a + 3 } \end{array} \right.$$

Least Common Multiple

$$\left(a^{2}-9a+3\right)\left(xa^{2}+33a-9\right)$$

Solution Steps

Factor the expressions that are not already factored.

$$a^{2}-9a+3=\left(a-\left(-\frac{1}{2}\sqrt{69}+\frac{9}{2}\right)\right)\left(a-\left(\frac{1}{2}\sqrt{69}+\frac{9}{2}\right)\right)$$

Identify all the factors and their highest power in all expressions. Multiply the highest powers of these factors to get the least common multiple.

$$\left(a^{2}-9a+3\right)\left(xa^{2}+33a-9\right)$$

Expand the expression.

$$xa^{4}-9xa^{3}+3xa^{2}+33a^{3}-306a^{2}+180a-27$$

Evaluate

$$xa^{2}+33a-9,\ a^{2}-9a+3$$