Solve for x, y
x=8
y=12
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9y+4=8^{2}+6\times 8
Consider the second equation. Insert the known values of variables into the equation.
9y+4=64+6\times 8
Calculate 8 to the power of 2 and get 64.
9y+4=64+48
Multiply 6 and 8 to get 48.
9y+4=112
Add 64 and 48 to get 112.
9y=112-4
Subtract 4 from both sides.
9y=108
Subtract 4 from 112 to get 108.
y=\frac{108}{9}
Divide both sides by 9.
y=12
Divide 108 by 9 to get 12.
x=8 y=12
The system is now solved.
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