Solve {c}{x=2+350}{0.65x+0.09y=388}

$$\left. \begin{array} { c } { x = 2 + 350 } \\ { 0.65 x + 0.09 y = 388 } \end{array} \right.$$

Solve for x, y

$$x=352$$

$$y = \frac{15920}{9} = 1768\frac{8}{9} \approx 1768.888888889$$

Solution Steps

Consider the first equation. Add 2 and 350 to get 352.

$$x=352$$

Consider the second equation. Insert the known values of variables into the equation.

$$0.65\times 352+0.09y=388$$

Multiply 0.65 and 352 to get 228.8.

$$228.8+0.09y=388$$

Subtract 228.8 from both sides.

$$0.09y=388-228.8$$

Subtract 228.8 from 388 to get 159.2.

$$0.09y=159.2$$

Divide both sides by 0.09.

$$y=\frac{159.2}{0.09}$$

Expand \frac{159.2}{0.09} by multiplying both numerator and the denominator by 100.

$$y=\frac{15920}{9}$$

The system is now solved.

$$x=352 y=\frac{15920}{9}$$