Solve {l}{x=-4}{text{Solvefor}ytext{where}}{y=-x^3-x^2-x}

$$\left. \begin{array} { l } { x = -4 }\\ { \text{Solve for } y \text{ where} } \\ { y = -x ^ {3} - x ^ {2} - x } \end{array} \right.$$

Solve for x, y

$$y=52$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=-\left(-4\right)^{3}-\left(-4\right)^{2}-\left(-4\right)$$

Calculate -4 to the power of 3 and get -64.

$$y=-\left(-64\right)-\left(-4\right)^{2}-\left(-4\right)$$

The opposite of -64 is 64.

$$y=64-\left(-4\right)^{2}-\left(-4\right)$$

Calculate -4 to the power of 2 and get 16.

$$y=64-16-\left(-4\right)$$

Subtract 16 from 64 to get 48.

$$y=48-\left(-4\right)$$

Multiply -1 and -4 to get 4.

$$y=48+4$$

Add 48 and 4 to get 52.

$$y=52$$

The system is now solved.

$$x=-4 y=52$$