Solve {c}{x+1=0}{3x-4y-19=0}

$$\left. \begin{array} { c } { x + 1 = 0 } \\ { 3 x - 4 y - 19 = 0 } \end{array} \right.$$

Solve for x, y

$$x=-1$$

$$y = -\frac{11}{2} = -5\frac{1}{2} = -5.5$$

Solution Steps

Consider the first equation. Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$x=-1$$

Consider the second equation. Insert the known values of variables into the equation.

$$3\left(-1\right)-4y-19=0$$

Multiply 3 and -1 to get -3.

$$-3-4y-19=0$$

Subtract 19 from -3 to get -22.

$$-22-4y=0$$

Add 22 to both sides. Anything plus zero gives itself.

$$-4y=22$$

Divide both sides by -4.

$$y=\frac{22}{-4}$$

Reduce the fraction \frac{22}{-4} to lowest terms by extracting and canceling out 2.

$$y=-\frac{11}{2}$$

The system is now solved.

$$x=-1 y=-\frac{11}{2}$$