Solve {c}{5x=9}{1+3y=x}

$$\left. \begin{array} { c } { 5 x = 9 } \\ { 1 + 3 y = x } \end{array} \right.$$

Solve for x, y

$$x = \frac{9}{5} = 1\frac{4}{5} = 1.8$$

$$y=\frac{4}{15}\approx 0.266666667$$

Solution Steps

Consider the first equation. Divide both sides by 5.

$$x=\frac{9}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$1+3y=\frac{9}{5}$$

Subtract 1 from both sides.

$$3y=\frac{9}{5}-1$$

Subtract 1 from \frac{9}{5} to get \frac{4}{5}.

$$3y=\frac{4}{5}$$

Divide both sides by 3.

$$y=\frac{\frac{4}{5}}{3}$$

Express \frac{\frac{4}{5}}{3} as a single fraction.

$$y=\frac{4}{5\times 3}$$

Multiply 5 and 3 to get 15.

$$y=\frac{4}{15}$$

The system is now solved.

$$x=\frac{9}{5} y=\frac{4}{15}$$