Solve {c}{(-4)^3*(-0.5)-(-2)^2}{div(-2/5)}

$$\left. \begin{array} { c } { ( - 4 ) ^ { 3 } \times ( - 0.5 ) - ( - 2 ) ^ { 2 } } \\ { \div ( - \frac { 2 } { 5 } ) } \end{array} \right.$$

Evaluate

$$42$$

Solution Steps

Calculate -4 to the power of 3 and get -64.

$$-64\left(-0.5\right)-\frac{\left(-2\right)^{2}}{-\frac{2}{5}}$$

Multiply -64 and -0.5 to get 32.

$$32-\frac{\left(-2\right)^{2}}{-\frac{2}{5}}$$

Calculate -2 to the power of 2 and get 4.

$$32-\frac{4}{-\frac{2}{5}}$$

Divide 4 by -\frac{2}{5} by multiplying 4 by the reciprocal of -\frac{2}{5}.

$$32-4\left(-\frac{5}{2}\right)$$

Express 4\left(-\frac{5}{2}\right) as a single fraction.

$$32-\frac{4\left(-5\right)}{2}$$

Multiply 4 and -5 to get -20.

$$32-\frac{-20}{2}$$

Divide -20 by 2 to get -10.

$$32-\left(-10\right)$$

The opposite of -10 is 10.

$$32+10$$

Add 32 and 10 to get 42.

$$42$$

Factor

$$2\times 3\times 7$$