Solve left(2x-1right)left(2x+1right)=4x^2-3x

$$\left( 2x-1 \right) \left( 2x+1 \right) = 4 { x }^{ 2 } -3x$$

Solve for x

$$x=\frac{1}{3}\approx 0.333333333$$

Steps for Solving Linear Equation

Consider \left(2x-1\right)\left(2x+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.

$$\left(2x\right)^{2}-1=4x^{2}-3x$$

Expand \left(2x\right)^{2}.

$$2^{2}x^{2}-1=4x^{2}-3x$$

Calculate 2 to the power of 2 and get 4.

$$4x^{2}-1=4x^{2}-3x$$

Subtract 4x^{2} from both sides.

$$4x^{2}-1-4x^{2}=-3x$$

Combine 4x^{2} and -4x^{2} to get 0.

$$-1=-3x$$

Swap sides so that all variable terms are on the left hand side.

$$-3x=-1$$

Divide both sides by -3.

$$x=\frac{-1}{-3}$$

Fraction \frac{-1}{-3} can be simplified to \frac{1}{3} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{3}$$