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Calculate Determinant
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det(\left(\begin{matrix}1&-2&3\\-3&4&-5\\-1&-7&8\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}1&-2&3&1&-2\\-3&4&-5&-3&4\\-1&-7&8&-1&-7\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
4\times 8-2\left(-5\right)\left(-1\right)+3\left(-3\right)\left(-7\right)=85
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-4\times 3-7\left(-5\right)+8\left(-3\right)\left(-2\right)=71
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
85-71
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
14
Subtract 71 from 85.
det(\left(\begin{matrix}1&-2&3\\-3&4&-5\\-1&-7&8\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
det(\left(\begin{matrix}4&-5\\-7&8\end{matrix}\right))-\left(-2det(\left(\begin{matrix}-3&-5\\-1&8\end{matrix}\right))\right)+3det(\left(\begin{matrix}-3&4\\-1&-7\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
4\times 8-\left(-7\left(-5\right)\right)-\left(-2\left(-3\times 8-\left(-\left(-5\right)\right)\right)\right)+3\left(-3\left(-7\right)-\left(-4\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-3-\left(-2\left(-29\right)\right)+3\times 25
Simplify.
14
Add the terms to obtain the final result.