\left( \begin{array} { l l } { 1 } & { 1 } \\ { 3 } & { y } \end{array} \right) \left( \begin{array} { l } { x } \\ { 1 } \end{array} \right) = \left( \begin{array} { l } { 4 } \\ { 1 } \end{array} \right)
Solve for x, y
x=3
y=-8
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x=4-1
Consider the first equation. Subtract 1 from both sides.
x=3
Subtract 1 from 4 to get 3.
3\times 3+y=1
Consider the second equation. Insert the known values of variables into the equation.
9+y=1
Multiply 3 and 3 to get 9.
y=1-9
Subtract 9 from both sides.
y=-8
Subtract 9 from 1 to get -8.
x=3 y=-8
The system is now solved.
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