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det(\left(\begin{matrix}1&-2&-4\\4&3&11\\2&-2&-11\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}1&-2&-4&1&-2\\4&3&11&4&3\\2&-2&-11&2&-2\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
3\left(-11\right)-2\times 11\times 2-4\times 4\left(-2\right)=-45
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
2\times 3\left(-4\right)-2\times 11-11\times 4\left(-2\right)=42
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-45-42
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-87
Subtract 42 from -45.
det(\left(\begin{matrix}1&-2&-4\\4&3&11\\2&-2&-11\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
det(\left(\begin{matrix}3&11\\-2&-11\end{matrix}\right))-\left(-2det(\left(\begin{matrix}4&11\\2&-11\end{matrix}\right))\right)-4det(\left(\begin{matrix}4&3\\2&-2\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
3\left(-11\right)-\left(-2\times 11\right)-\left(-2\left(4\left(-11\right)-2\times 11\right)\right)-4\left(4\left(-2\right)-2\times 3\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-11-\left(-2\left(-66\right)\right)-4\left(-14\right)
Simplify.
-87
Add the terms to obtain the final result.