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det(\left(\begin{matrix}3&-1&-1\\-1&2&2\\-1&-1&3\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}3&-1&-1&3&-1\\-1&2&2&-1&2\\-1&-1&3&-1&-1\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
3\times 2\times 3-2\left(-1\right)-\left(-\left(-1\right)\right)=19
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-2\left(-1\right)-2\times 3+3\left(-1\right)\left(-1\right)=-1
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
19-\left(-1\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
20
Subtract -1 from 19.
det(\left(\begin{matrix}3&-1&-1\\-1&2&2\\-1&-1&3\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
3det(\left(\begin{matrix}2&2\\-1&3\end{matrix}\right))-\left(-det(\left(\begin{matrix}-1&2\\-1&3\end{matrix}\right))\right)-det(\left(\begin{matrix}-1&2\\-1&-1\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
3\left(2\times 3-\left(-2\right)\right)-\left(-\left(-3-\left(-2\right)\right)\right)-\left(-\left(-1\right)-\left(-2\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
3\times 8-\left(-\left(-1\right)\right)-3
Simplify.
20
Add the terms to obtain the final result.