\left\{ \begin{array} { l } { z + y = 3 } \\ { 5 = 3 + y } \end{array} \right.
Solve for z, y
y=2
z=1
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3+y=5
Consider the second equation. Swap sides so that all variable terms are on the left hand side.
y=5-3
Subtract 3 from both sides.
y=2
Subtract 3 from 5 to get 2.
z+2=3
Consider the first equation. Insert the known values of variables into the equation.
z=3-2
Subtract 2 from both sides.
z=1
Subtract 2 from 3 to get 1.
z=1 y=2
The system is now solved.
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