\left\{ \begin{array} { l } { y + x = 2 } \\ { x + 2 = 3 } \end{array} \right.
Solve for y, x
x=1
y=1
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x=3-2
Consider the second equation. Subtract 2 from both sides.
x=1
Subtract 2 from 3 to get 1.
y+1=2
Consider the first equation. Insert the known values of variables into the equation.
y=2-1
Subtract 1 from both sides.
y=1
Subtract 1 from 2 to get 1.
y=1 x=1
The system is now solved.
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