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x=-\frac{1}{3}+6
Consider the first equation. Add 6 to both sides.
x=\frac{17}{3}
Add -\frac{1}{3} and 6 to get \frac{17}{3}.
\frac{\frac{17}{3}-3}{5}+y=\frac{17}{3}+\frac{21}{5}
Consider the second equation. Insert the known values of variables into the equation.
3\left(\frac{17}{3}-3\right)+15y=85+63
Multiply both sides of the equation by 15, the least common multiple of 5,3.
3\times \frac{8}{3}+15y=85+63
Subtract 3 from \frac{17}{3} to get \frac{8}{3}.
8+15y=85+63
Multiply 3 and \frac{8}{3} to get 8.
8+15y=148
Add 85 and 63 to get 148.
15y=148-8
Subtract 8 from both sides.
15y=140
Subtract 8 from 148 to get 140.
y=\frac{140}{15}
Divide both sides by 15.
y=\frac{28}{3}
Reduce the fraction \frac{140}{15} to lowest terms by extracting and canceling out 5.
x=\frac{17}{3} y=\frac{28}{3}
The system is now solved.