\left\{ \begin{array} { l } { x - 4 y + 3 = 0 } \\ { x = 1 } \end{array} \right.
Solve for x, y
x=1
y=1
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1-4y+3=0
Consider the first equation. Insert the known values of variables into the equation.
4-4y=0
Add 1 and 3 to get 4.
-4y=-4
Subtract 4 from both sides. Anything subtracted from zero gives its negation.
y=\frac{-4}{-4}
Divide both sides by -4.
y=1
Divide -4 by -4 to get 1.
x=1 y=1
The system is now solved.
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