Solve {l}{x-3x=13}{x+y=1}

$$\left\{ \begin{array} { l } { x - 3 x = 13 } \\ { x + y = 1 } \end{array} \right.$$

Solve for x, y

$$x = -\frac{13}{2} = -6\frac{1}{2} = -6.5$$

$$y = \frac{15}{2} = 7\frac{1}{2} = 7.5$$

Solution Steps

Consider the first equation. Combine x and -3x to get -2x.

$$-2x=13$$

Divide both sides by -2.

$$x=-\frac{13}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$-\frac{13}{2}+y=1$$

Add \frac{13}{2} to both sides.

$$y=1+\frac{13}{2}$$

Add 1 and \frac{13}{2} to get \frac{15}{2}.

$$y=\frac{15}{2}$$

The system is now solved.

$$x=-\frac{13}{2} y=\frac{15}{2}$$