\left\{ \begin{array} { l } { x = 3 } \\ { x - y = 6 } \end{array} \right.
Solve for x, y
x=3
y=-3
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\left\{ \begin{array} { l } { x = 3 } \\ { x - y = 6 } \end{array} \right.
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3-y=6
Consider the second equation. Insert the known values of variables into the equation.
-y=6-3
Subtract 3 from both sides.
-y=3
Subtract 3 from 6 to get 3.
y=-3
Divide both sides by -1.
x=3 y=-3
The system is now solved.
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