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2\times 2^{2}-2+a=5
Consider the second equation. Insert the known values of variables into the equation.
2^{3}-2+a=5
To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.
8-2+a=5
Calculate 2 to the power of 3 and get 8.
6+a=5
Subtract 2 from 8 to get 6.
a=5-6
Subtract 6 from both sides.
a=-1
Subtract 6 from 5 to get -1.
x=2 a=-1
The system is now solved.