\left\{ \begin{array} { l } { x + y = 3 } \\ { z + y = 5 } \\ { x + z = 4 } \end{array} \right.
Solve for x, y, z
x=1
y=2
z=3
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x=-y+3
Solve x+y=3 for x.
-y+3+z=4
Substitute -y+3 for x in the equation x+z=4.
y=-z+5 z=y+1
Solve the second equation for y and the third equation for z.
z=-z+5+1
Substitute -z+5 for y in the equation z=y+1.
z=3
Solve z=-z+5+1 for z.
y=-3+5
Substitute 3 for z in the equation y=-z+5.
y=2
Calculate y from y=-3+5.
x=-2+3
Substitute 2 for y in the equation x=-y+3.
x=1
Calculate x from x=-2+3.
x=1 y=2 z=3
The system is now solved.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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