Solve {l}{x+y=28}{2*12x=184}

$$\left\{ \begin{array} { l } { x + y = 28 } \\ { 2 \cdot 12 x = 184 } \end{array} \right.$$

Solve for x, y

$$x = \frac{23}{3} = 7\frac{2}{3} \approx 7.666666667$$

$$y = \frac{61}{3} = 20\frac{1}{3} \approx 20.333333333$$

Solution Steps

Consider the second equation. Multiply 2 and 12 to get 24.

$$24x=184$$

Divide both sides by 24.

$$x=\frac{184}{24}$$

Reduce the fraction \frac{184}{24} to lowest terms by extracting and canceling out 8.

$$x=\frac{23}{3}$$

Consider the first equation. Insert the known values of variables into the equation.

$$\frac{23}{3}+y=28$$

Subtract \frac{23}{3} from both sides.

$$y=28-\frac{23}{3}$$

Subtract \frac{23}{3} from 28 to get \frac{61}{3}.

$$y=\frac{61}{3}$$

The system is now solved.

$$x=\frac{23}{3} y=\frac{61}{3}$$