\left\{ \begin{array} { l } { x + 4 y = 9 } \\ { 3 x + 7 u = 2 } \end{array} \right.
Solve for x, y
x=\frac{2-7u}{3}
y=\frac{7u+25}{12}
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3x+7u=2,x+4y=9
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
3x+7u=2
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
3x=2-7u
Subtract 7u from both sides of the equation.
x=\frac{2-7u}{3}
Divide both sides by 3.
\frac{2-7u}{3}+4y=9
Substitute \frac{2-7u}{3} for x in the other equation, x+4y=9.
4y=\frac{7u+25}{3}
Subtract \frac{2-7u}{3} from both sides of the equation.
y=\frac{7u+25}{12}
Divide both sides by 4.
x=\frac{2-7u}{3},y=\frac{7u+25}{12}
The system is now solved.
Examples
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Linear equation
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Arithmetic
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Matrix
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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