\left\{ \begin{array} { l } { x + 2 y = 3 } \\ { 3 x + 5 y = m } \\ { x + y = 1 } \end{array} \right.
Solve for x, y, m
x=-1
y=2
m=7
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3x+5y=m x+2y=3 x+y=1
Reorder the equations.
m=3x+5y
Solve 3x+5y=m for m.
y=-\frac{1}{2}x+\frac{3}{2} x=-y+1
Solve the second equation for y and the third equation for x.
x=-\left(-\frac{1}{2}x+\frac{3}{2}\right)+1
Substitute -\frac{1}{2}x+\frac{3}{2} for y in the equation x=-y+1.
x=-1
Solve x=-\left(-\frac{1}{2}x+\frac{3}{2}\right)+1 for x.
y=-\frac{1}{2}\left(-1\right)+\frac{3}{2}
Substitute -1 for x in the equation y=-\frac{1}{2}x+\frac{3}{2}.
y=2
Calculate y from y=-\frac{1}{2}\left(-1\right)+\frac{3}{2}.
m=3\left(-1\right)+5\times 2
Substitute 2 for y and -1 for x in the equation m=3x+5y.
m=7
Calculate m from m=3\left(-1\right)+5\times 2.
x=-1 y=2 m=7
The system is now solved.
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