\left\{ \begin{array} { l } { H + 0 = 24 } \\ { 0 + L = 28 } \\ { L + A = 13 } \end{array} \right.
Solve for H, L, A
H=24
L=28
A=-15
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H=24
Consider the first equation. Anything plus zero gives itself.
L=28
Consider the second equation. Anything plus zero gives itself.
28+A=13
Consider the third equation. Insert the known values of variables into the equation.
A=13-28
Subtract 28 from both sides.
A=-15
Subtract 28 from 13 to get -15.
H=24 L=28 A=-15
The system is now solved.
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