\left\{ \begin{array} { l } { C = 1 } \\ { 4 a + 2 b + c = 4 } \\ { 9 a + 3 b + c = 10 } \end{array} \right.
Solve for C, a, b, c
C=1
a=\frac{c}{6}+\frac{4}{3}
b=-\frac{5c}{6}-\frac{2}{3}
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