Solve {l}{44x+90y=7006}{44x+4=2476}

$$\left\{ \begin{array} { l } { 44 x + 90 y = 7006 } \\ { 44 x + 4 = 2476 } \end{array} \right.$$

Solve for x, y

$$x = \frac{618}{11} = 56\frac{2}{11} \approx 56.181818182$$

$$y = \frac{2267}{45} = 50\frac{17}{45} \approx 50.377777778$$

Solution Steps

Consider the second equation. Subtract 4 from both sides.

$$44x=2476-4$$

Subtract 4 from 2476 to get 2472.

$$44x=2472$$

Divide both sides by 44.

$$x=\frac{2472}{44}$$

Reduce the fraction \frac{2472}{44} to lowest terms by extracting and canceling out 4.

$$x=\frac{618}{11}$$

Consider the first equation. Insert the known values of variables into the equation.

$$44\times \frac{618}{11}+90y=7006$$

Multiply 44 and \frac{618}{11} to get 2472.

$$2472+90y=7006$$

Subtract 2472 from both sides.

$$90y=7006-2472$$

Subtract 2472 from 7006 to get 4534.

$$90y=4534$$

Divide both sides by 90.

$$y=\frac{4534}{90}$$

Reduce the fraction \frac{4534}{90} to lowest terms by extracting and canceling out 2.

$$y=\frac{2267}{45}$$

The system is now solved.

$$x=\frac{618}{11} y=\frac{2267}{45}$$