Solve {l}{3x=64-2}{3x-4y=2}

$$\left\{ \begin{array} { l } { 3 x = 64 - 2 } \\ { 3 x - 4 y = 2 } \end{array} \right.$$

Solve for x, y

$$x = \frac{62}{3} = 20\frac{2}{3} \approx 20.666666667$$

$$y=15$$

Solution Steps

Consider the first equation. Subtract 2 from 64 to get 62.

$$3x=62$$

Divide both sides by 3.

$$x=\frac{62}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$3\times \frac{62}{3}-4y=2$$

Multiply 3 and \frac{62}{3} to get 62.

$$62-4y=2$$

Subtract 62 from both sides.

$$-4y=2-62$$

Subtract 62 from 2 to get -60.

$$-4y=-60$$

Divide both sides by -4.

$$y=\frac{-60}{-4}$$

Divide -60 by -4 to get 15.

$$y=15$$

The system is now solved.

$$x=\frac{62}{3} y=15$$