Solve {l}{3x+4=1}{3x-y=2}

$$\left\{ \begin{array} { l } { 3 x + 4 = 1 } \\ { 3 x - y = 2 } \end{array} \right.$$

Solve for x, y

$$x=-1$$

$$y=-5$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$3x=1-4$$

Subtract 4 from 1 to get -3.

$$3x=-3$$

Divide both sides by 3.

$$x=\frac{-3}{3}$$

Divide -3 by 3 to get -1.

$$x=-1$$

Consider the second equation. Insert the known values of variables into the equation.

$$3\left(-1\right)-y=2$$

Multiply 3 and -1 to get -3.

$$-3-y=2$$

Add 3 to both sides.

$$-y=2+3$$

Add 2 and 3 to get 5.

$$-y=5$$

Divide both sides by -1.

$$y=-5$$

The system is now solved.

$$x=-1 y=-5$$