Solve {l}{3x+1=7}{2y-1=3}

$$\left\{ \begin{array} { l } { 3 x + 1 = 7 } \\ { 2 y - 1 = 3 } \end{array} \right.$$

Solve for x, y

$$x=2$$

$$y=2$$

Solution Steps

Consider the first equation. Subtract 1 from both sides.

$$3x=7-1$$

Subtract 1 from 7 to get 6.

$$3x=6$$

Divide both sides by 3.

$$x=\frac{6}{3}$$

Divide 6 by 3 to get 2.

$$x=2$$

Consider the second equation. Add 1 to both sides.

$$2y=3+1$$

Add 3 and 1 to get 4.

$$2y=4$$

Divide both sides by 2.

$$y=\frac{4}{2}$$

Divide 4 by 2 to get 2.

$$y=2$$

The system is now solved.

$$x=2 y=2$$