\left\{ \begin{array} { l } { 3 ( x - 10 ) = 2 x - 10 } \\ { 3 ( y + 10 ) = 2 y + 10 } \end{array} \right.
Solve for x, y
x=20
y=-20
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3x-30=2x-10
Consider the first equation. Use the distributive property to multiply 3 by x-10.
3x-30-2x=-10
Subtract 2x from both sides.
x-30=-10
Combine 3x and -2x to get x.
x=-10+30
Add 30 to both sides.
x=20
Add -10 and 30 to get 20.
3y+30=2y+10
Consider the second equation. Use the distributive property to multiply 3 by y+10.
3y+30-2y=10
Subtract 2y from both sides.
y+30=10
Combine 3y and -2y to get y.
y=10-30
Subtract 30 from both sides.
y=-20
Subtract 30 from 10 to get -20.
x=20 y=-20
The system is now solved.
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