Solve {l}{3=-k+6}{4=b}

$$\left\{ \begin{array} { l } { 3 = - k + 6 } \\ { 4 = b } \end{array} \right.$$

Solve for k, b

$$k=3$$

$$b=4$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$-k+6=3$$

Subtract 6 from both sides.

$$-k=3-6$$

Subtract 6 from 3 to get -3.

$$-k=-3$$

Divide both sides by -1.

$$k=\frac{-3}{-1}$$

Fraction \frac{-3}{-1} can be simplified to 3 by removing the negative sign from both the numerator and the denominator.

$$k=3$$

Consider the second equation. Swap sides so that all variable terms are on the left hand side.

$$b=4$$

The system is now solved.

$$k=3 b=4$$