Solve {l}{3=-2+b}{-2=3k+b}

$$\left\{ \begin{array} { l } { 3 = - 2 + b } \\ { - 2 = 3 k + b } \end{array} \right.$$

Solve for b, k

$$b=5$$

$$k = -\frac{7}{3} = -2\frac{1}{3} \approx -2.333333333$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$-2+b=3$$

Add 2 to both sides.

$$b=3+2$$

Add 3 and 2 to get 5.

$$b=5$$

Consider the second equation. Insert the known values of variables into the equation.

$$-2=3k+5$$

Swap sides so that all variable terms are on the left hand side.

$$3k+5=-2$$

Subtract 5 from both sides.

$$3k=-2-5$$

Subtract 5 from -2 to get -7.

$$3k=-7$$

Divide both sides by 3.

$$k=-\frac{7}{3}$$

The system is now solved.

$$b=5 k=-\frac{7}{3}$$