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28x=3\times 2
Consider the first equation. Insert the known values of variables into the equation.
28x=6
Multiply 3 and 2 to get 6.
x=\frac{6}{28}
Divide both sides by 28.
x=\frac{3}{14}
Reduce the fraction \frac{6}{28} to lowest terms by extracting and canceling out 2.
x=\frac{3}{14} y=2
The system is now solved.