Solve {l}{25=a^2/2*(5-h)^2}{2h=0,5asqrt{(h-2)^2-4}}

$$\left\{ \begin{array} { l } { 25 = \frac { a ^ { 2 } } { 2 } \times ( 5 - h ) ^ { 2 } } \\ { 2 h = 0,5 a \sqrt { ( h - 2 ) ^ { 2 } - 4 } } \end{array} \right.$$

Solve for a, h

$$a=-\sqrt{2}\approx -1.414213562\text{, }h=0$$

$$a=-\frac{3\sqrt{2}\left(\sqrt{22}\cos(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})-2\right)}{11\left(\cos(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})\right)^{2}-2}\approx -1.293396993\text{, }h=\frac{5\left(-\sqrt{22}\cos(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})+4\right)}{6}\approx -0.467051379$$

$$a=-\frac{12\sqrt{2}}{-\sqrt{22}\cos(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})-\sqrt{66}\sin(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})+4}\approx 6.899841318\text{, }h=\frac{5\left(\sqrt{22}\left(\sqrt{3}\sin(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})+\cos(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})\right)+8\right)}{12}\approx 6.024816005$$

$$a=\sqrt{2}\approx 1.414213562\text{, }h=0$$

$$a=\frac{12\sqrt{2}}{\sqrt{66}\sin(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})-\sqrt{22}\cos(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})+4}\approx 12.677512138\text{, }h=\frac{5\left(\sqrt{22}\left(-\sqrt{3}\sin(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})+\cos(\frac{\arccos(\frac{98\sqrt{22}}{605})}{3})\right)+8\right)}{12}\approx 4.442235374$$