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3y+x=16
Consider the first equation. Combine 2y and y to get 3y.
-27+10x+y=100y+10x+2y
Consider the second equation. Subtract 227 from 200 to get -27.
-27+10x+y=102y+10x
Combine 100y and 2y to get 102y.
-27+10x+y-102y=10x
Subtract 102y from both sides.
-27+10x-101y=10x
Combine y and -102y to get -101y.
-27+10x-101y-10x=0
Subtract 10x from both sides.
-27-101y=0
Combine 10x and -10x to get 0.
-101y=27
Add 27 to both sides. Anything plus zero gives itself.
y=-\frac{27}{101}
Divide both sides by -101.
3\left(-\frac{27}{101}\right)+x=16
Consider the first equation. Insert the known values of variables into the equation.
-\frac{81}{101}+x=16
Multiply 3 and -\frac{27}{101} to get -\frac{81}{101}.
x=16+\frac{81}{101}
Add \frac{81}{101} to both sides.
x=\frac{1697}{101}
Add 16 and \frac{81}{101} to get \frac{1697}{101}.
y=-\frac{27}{101} x=\frac{1697}{101}
The system is now solved.